-x^2+10x+1200=325

Solution for -x^2+10x+1200=325 equation:

-x^2+10x+1200=325

We move all terms to the left:

-x^2+10x+1200-(325)=0

We add all the numbers together, and all the variables

-1x^2+10x+875=0

a = -1; b = 10; c = +875;
Δ = b2-4ac
Δ = 102-4·(-1)·875
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-60}{2*-1}=\frac{-70}{-2}
=+35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+60}{2*-1}=\frac{50}{-2}
=-25
$